Yes but I think he is saying that if the left/what you compare to is not a const... | Hacker News

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rguldener on March 1, 2014 | parent | context | favorite | on: A brief history of one line fixes

Yes but I think he is saying that if the left/what you compare to is not a constant then it will not warn you (if the type agrees, as it should anyway for a comparison).

cbhl on March 1, 2014 [–]

If the left is a function call, it will still error out because you can't assign to it.

If you're doing

    if (var1 == var2)

then yoda expressions won't save you, however.

koenigdavidmj on March 2, 2014 | [–]

Also, in C++ you can assign to the return value of a function returning a reference.

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